The rectangle is 8 times the length of the width. Find the area and perimeter of the rectangle

The rectangle is 8 times the length of the width. Find the area and perimeter of the rectangle if the width is 42 cm less than the length.

Let us denote through the variable m the number of centimeters to which the width of this figure is equal.

Therefore, according to the conditions of the problem, we can express the length as 8m.

Since it is known that the length is 42 cm larger, then we write down the equation and calculate the size of the figure:

8m – m = 42;

7m = 42;

m = 6;

42 + 6 = 48.

Let’s calculate what the area of a given figure is equal to:

48 * 6 = 288.

Let’s calculate what the perimeter of a given figure is:

(48 + 6) * 2 = 108.

Answer: The area of a given figure is 288 cm2, and its perimeter is 108 cm.