The rectangle is 8cm wide and 1 dm shorter than the length. find the perimeter and area of the rectangle.
April 9, 2021 | education
| Given:
a – the width of the rectangle, b – the length of the rectangle
a = 8 cm, which is 1 dm less than b
Find: P, S
Decision:
1 dm = 10 cm, then b = 8 + 10 = 18 cm.
P is the perimeter of the rectangle.
P = (a + b) * 2 = (8 + 18) * 2 = 52 cm.
S is the area of the rectangle.
S = a * b = 8 * 18 = 144 cm 2
Answer: P = 52 cm, S = 144 cm 2
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