The rectangle is 8cm wide and 1 dm shorter than the length. find the perimeter and area of the rectangle.

Given:

a – the width of the rectangle, b – the length of the rectangle

a = 8 cm, which is 1 dm less than b

Find: P, S

Decision:

1 dm = 10 cm, then b = 8 + 10 = 18 cm.

P is the perimeter of the rectangle.

P = (a + b) * 2 = (8 + 18) * 2 = 52 cm.

S is the area of the rectangle.

S = a * b = 8 * 18 = 144 cm 2

Answer: P = 52 cm, S = 144 cm 2



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