The rectangle is divided into rectangles, the perimeters of two of them are 20 m and 40 m

The rectangle is divided into rectangles, the perimeters of two of them are 20 m and 40 m, find the perimeter of the large rectangle.

Since the rectangle is split into two other rectangles, they therefore have one side in common. Let the length of the common side be equal to a. The length of the second side of the first rectangle is at, and the second is at. So the perimeter of the first rectangle can be written as:

2 * (a + b) = 20;

a + b = 10.

Perimeter of the second:

2 * (a + c) = 20;

a + c = 20.

The perimeter of the large rectangle is as follows:

2 * (a + b + c)

It means that there is not enough data for the solution.