# The rectangle is divided into squares, the side length of the smallest square is 1 cm,

The rectangle is divided into squares, the side length of the smallest square is 1 cm, which is equal to the perimeter of the rectangle.

By the condition of the problem, the side of the small square is 1 cm.

Adjacent to it is a larger square, the side of which can be found as two sides of small squares, that is, the side of the middle square is: 1 + 1 = 2 (cm).

The side of the small square and the side of the middle square make up the side of the rectangle, or rather its width.

Let us find what the width of the rectangle is equal to if it consists of sides equal to 1 cm and 2 cm:

1 + 2 = 3 (cm) – the width of the rectangle.

The other side of the rectangle is one side of the middle square and two sides of the small square. Thus, we calculate the length of the rectangle if it consists of sides equal to 1 cm, 1 cm and 3 cm:

1 + 1 + 3 = 5 (cm) – the length of the rectangle.

Now we calculate the perimeter of a rectangle with sides of 3 cm and 5 cm, equal to the doubled sum of its two sides:

P = 2 (3 + 5) = 2 * 8 = 16 (cm).

Answer: The perimeter of the rectangle is 16 cm.

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