# The rectangular box has a length of 8 dm, a width of 5 dm and a height of 3 dm. show in the picture how to place rectangular

**The rectangular box has a length of 8 dm, a width of 5 dm and a height of 3 dm. show in the picture how to place rectangular bars in this box in order to fill it completely, if each bar is 5dm long, 2dm wide and 1dm high. How many of these bars fit in this box in this case? what capacity does the box have?**

When choosing a laying method, take into account the following ratios:

the width of the box and the length of the bar coincide – 5 dm each;

the length of the box (8 dm) is a multiple of the width of the bar (2 dm);

the height of the box (3 dm) is a multiple of the height of the bar (1 dm).

You need to put the bars in the box in layers of 4 bars, orienting them along the width of the box.

In total, you will get 3 layers of 4 bars. Total 3 * 4 = 12 bars.

You can determine the capacity of the box using calculations:

Box volume V:

V = 5 dm * 8 dm * 3 dm = 120 dm ^ 3;

The volume of the bar is v = 2 dm * 5 dm * 1 dm = 10 dm ^ 3.

Dividing the volume of the box by the volume of one bar, we find how many bars fit in the box:

120 dm ^ 2/10 dm ^ 3 = 12.