The relative density of the substance in terms of hydrogen is 57, the mass fraction of carbon in it is 84.21%.

The relative density of the substance in terms of hydrogen is 57, the mass fraction of carbon in it is 84.21%. Establish the molecular formula of the hydrocarbon.

Given: w (C) = 84.21 or 0.8421, D (H2) = 57
Find: CxHy
Decision:
Mr (CxHy) = D (H2) * M (H2) = 57 * 2 = 114
w (H) = 1-0.8421 = 0.1579
n (C) = (114 * 0.8421) / 12 = 8
n (H) = (112 * 0.1579) / 1 = 18
CxHy = n (C): n (H) = 8:18
C8H18- octane



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