The relative humidity of air in a closed vessel is 30% what the relative humidity will be if the volume

The relative humidity of air in a closed vessel is 30% what the relative humidity will be if the volume of the vessel is reduced by 2 times.

The relative humidity can be calculated using the formula:
φ = Pn / P * 100%, where Pn is the partial pressure of the gas, P is the equilibrium pressure of saturated steam.
For a constant temperature process, the following relationship is valid:
p1 * V1 = p2 * V2, where V2 = 0.5 V1.
p2 = p1 * V1 / V2 = p1 * V1 / (0.5 * V1) = 2p1.
Since p2 = 2p1, the saturated vapor pressure will double.
φ2 = 2Pn / P * 100% = 2φ1 = 2 * 30% = 60%.
Answer: The relative humidity in a closed vessel will be 60%.



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