# The resistance of a conductor 50 meters long with a cross-sectional area of 2 mm2 is 15 Ohm.

The resistance of a conductor 50 meters long with a cross-sectional area of 2 mm2 is 15 Ohm. Which is the resistivity of the alloy from which the wire is made?

To find the desired resistivity of the alloy from which the taken conductor is made, we will use the formula: R = ρ * l / S, from where we express: ρ = R * S / l.

Variables: R – resistance of the taken conductor (R = 15 Ohm); S – cross-sectional area (S = 2 mm2); l – length (l = 50 m).

Let’s calculate: ρ = R * S / l = 15 * 2/50 = 0.6 Ohm * mm2 / m.

Answer: The taken conductor was made of an alloy that has a specific electrical resistance of 0.6 Ohm * mm2 / m.

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