The resistance of one conductor is n times greater than the resistance of the other, how many times is the resistance
| December 13, 2020 | education
The resistance of one conductor is n times greater than the resistance of the other, how many times is the resistance of their parallel connection different from the resistance of their series connection?
Let R be the resistance of the first conductor, then the second – Rn.
Rposl = R + Rn = R (n + 1) – sequential. The sum of all resistances.
Rpair = R * Rn / (R + Rn) = Rn / (n + 1) – parallel. For two: divide the product by the sum.
Rpair / Rposl = [Rn / (n + 1)] / R (n + 1) = n / [(n + 1) ^ 2].
Answer: n / [(n + 1) ^ 2] times.
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