The resistance of one of three identical electric lamps connected in parallel is 300 ohms, and the current strength

The resistance of one of three identical electric lamps connected in parallel is 300 ohms, and the current strength is not 0.4 A. determine the voltage across the lamps.

To find the voltage across the lamps, we will use the formula: U = I * R = 3 * I1 * (R1 / 3) = I1 * R1.

Variable values: I1 – current in each lamp (I1 = 0.4 A); R1 is the resistance of each lamp (R1 = 300 ohms).

Calculation: U = I1 * R1 = 0.4 * 300 = 120 V.

Answer: The voltage on the lamps taken is 120 V.



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