The resultant of two mutually perpendicular forces is equal to 10n one of the forces is equal to 6n what acceleration

The resultant of two mutually perpendicular forces is equal to 10n one of the forces is equal to 6n what acceleration the second force will impart to a body weighing 4 kg.

These tasks: Fр (resultant of two perpendicular forces) = 10 N; F1 (value of the first force) = 6 N; m (body weight) = 4 kg.

1) The second force (Pythagorean theorem): Fр2 = F1 ^ 2 + F2 ^ 2 and F2 = √ (Fр2 – F1 ^ 2) = √ (10 ^ 2 – 6 ^ 2) = 8 N.

2) Acceleration of a given body under the action of the second force (Newton’s second law): a = F2 / m = 8/4 = 2 m / s2.

Answer: Under the action of the second force, a given body should move with an acceleration of 2 m / s2.