The rocket lifted a load weighing 6 tons to a height of 1000 km above

The rocket lifted a load weighing 6 tons to a height of 1000 km above the surface of the Earth. How much did the force of gravity acting on the load decrease during lifting?

Data: m (cargo weight) = 6 t (6000 kg); h (cargo height) = 1000 km (10 ^ 6 m).

Constants: g (acceleration of gravity at the surface) = 9.81 m / s2; R (radius of the Earth) = 6356863 m; G (gravitational constant) = 6.67 * 10 ^ -11 m3 / (kg * s2); M (mass of the Earth) = 5.97219 * 10 ^ 24 kg;.

1) Acceleration of gravity per 1000 km: g1 = G * M / (R + h) 2 = 6.67 * 10 ^ -11 * 5.97219 * 10 ^ 24 / (6356863 + 10 ^ 6) ^ 2 = 7 , 36 m / s2.

2) Decrease in gravity: ΔFt = m * (g – g1) = 6000 * (9.81 – 7.36) = 14700 N (14.7 kN).