The rocket moves with an acceleration of 45 m / s2 and at some point in time reaches a speed of 900 m / s.

The rocket moves with an acceleration of 45 m / s2 and at some point in time reaches a speed of 900 m / s. What path will it cover in the next 2 s?

If we assume that the rocket is moving uniformly accelerated, then the path formula:
S = ((a * t ^ 2) / 2) + V0 * t, where a is the acceleration of the rocket (45 m / s ^ 2), t is the time of movement of the rocket (2 s), V0 is the initial velocity of the rocket (900 m /with). The moment the rocket reaches a speed of 900 m / s will be the starting point of reference.
It follows from this:
S = ((45 * 2 ^ 2) / 2) + 900 * 2 = ((45 * 4) / 2) +1800 = 180/2 + 1800 = 1890 m.
Check: m = (m / s ^ 2) * s ^ 2 + (m / s) * s = m + m = m.
Answer. In 2 seconds, the rocket will cover a distance of 1890 m.