The rope can withstand a maximum load of 2.4 kN. What is the greatest acceleration
| February 27, 2021 | education
The rope can withstand a maximum load of 2.4 kN. What is the greatest acceleration with the help of this rope can a load weighing 200 kg be lifted?
To find the value of the greatest acceleration of the load during lifting, we will use Newton’s second law: m * a = Fmax – m * g, whence a = (Fmax – m * g) / m.
Constants and variables: Fmax – maximum load on the cable (Fmax = 2.4 kN = 2.4 * 10 ^ 3 N); m is the mass of the load on the cable (m = 200 kg); g – acceleration due to gravity (g ≈ 10 m / s2).
Calculation: a = (Fmax – m * g) / m = (2.4 * 10 ^ 3 – 200 * 10) / 200 = 400/200 = 2 m / s2.
Answer: The maximum acceleration of the load being lifted is 2 m / s2.
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