The rope holds a body with a weight of not more than 2500 N. A load of 200 kg is lifted on the rope.

The rope holds a body with a weight of not more than 2500 N. A load of 200 kg is lifted on the rope. At what acceleration will the rope break?

Let’s define the force of gravity acting on the load:

F = m * g, where m is the mass, g is the acceleration of gravity.

F = 200 * 10 = 2000 n

Then the safety margin will be:

2500 – 2000 = 500 n.

Using Newton’s second law, we find the maximum acceleration:

F = m * a;

a = F / m.

a = 500/200 = 2.5 m / s ^ 2.

Answer: acceleration during lifting should not exceed 2.5 m / s ^ 2.