The rope is 5m long and weighs 8kg and lies on the ground. The rope was lifted at one end to a height equal

The rope is 5m long and weighs 8kg and lies on the ground. The rope was lifted at one end to a height equal to its length. What kind of mechanical work was done?

To find out the mechanical work performed when lifting the specified rope, we use the formula (we take into account that the movement of the specified rope is taken to be the movement of its center of mass): Amech = F * S = mk * g * Scm = mk * g * l / 2.

Const: g – acceleration due to gravity (g ≈ 9.81 m / s2).

Data: mk – the mass of the specified rope (mk = 8 kg); l – rope length (l = 5 m).

Let’s perform the calculation: Amech = mk * g * l / 2 = 8 * 9.81 * 5/2 = 196.2 J.

Answer: The mechanical work performed when lifting the indicated rope is 196.2 J.