The rope withstands a motionlessly suspended load with a maximum mass of m1 = 450kg.

| September 8, 2021 | education

The rope withstands a motionlessly suspended load with a maximum mass of m1 = 450kg. What is the maximum acceleration and it is possible to lift a load weighing m2 = 400kg, suspended on this cable, so that it does not break off?

To determine the value of the maximum acceleration of the second load, we will use the equality: m1 * g = Tmax (maximum load) = m2 * g + m2 * a2, whence a2 = (m1 * g – m2 * g) / m2.

Variables and constants: m1 is the mass of the first load (m1 = 450 kg); g – acceleration due to gravity (g ≈ 10 m / s2); m2 is the mass of the second cargo (m2 = 400 kg).

Let’s calculate: a2 = (m1 * g – m2 * g) / m2 = (450 * 10 – 400 * 10) / 400 = 1.25 m / s2.

Answer: The second load can be lifted with a maximum acceleration of 1.25 m / s2.



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