The same amount of heat was spent on heating a brick weighing 4 kg by 105 degrees

The same amount of heat was spent on heating a brick weighing 4 kg by 105 degrees, as for heating water of the same mass by 22 degrees, determine the specific heat of the brick.

The amount of heat consumed for heating water:
Q2 = c * m2 * ∆t, where c2 is the specific heat capacity of the substance, m2 is the mass of the substance, ∆t2 is the temperature change.
Specific heat of water c2 = 4200 J / kg * K, according to the reference book.
Let’s determine the amount of heat consumed for heating water:
Q2 = c * m2 * ∆t = 4200 * 4 * 22 = 369600 J.
The amount of heat consumed to heat the brick:
Q1 = c * m1 * ∆t1, where c1 is the specific heat capacity of the substance, m2 is the mass of the substance, ∆t1 is the temperature change.
Let us express the expression c1 from this:
с1 = Q1 / (m1 * ∆t1).
Taking into account that Q1 = Q2, we have:
с1 = Q2 / (m1 * ∆t1) = 369600 / (4 * 105) = 880 J / kg * K.
Answer: the specific heat capacity of the brick is 880 J / kg * K.