The same mass of water was heated first by 15 ° and then by 45 ° in which case more heat
| August 7, 2021 | education
The same mass of water was heated first by 15 ° and then by 45 ° in which case more heat was consumed and how many times.
Task data: Δt1 (initial change in water temperature) = 15 ºС; Δt2 (second temperature change) = 45 ºС; an increase in the specific heat capacity of water with an increase in temperature is not taken into account; the mass of water taken is constant.
Comparison of the consumed heat is determined by the formula: k = Q2 / Q1 = Cw * m * Δt2 / (Cw * m * Δt1) = Δt2 / Δt1 = 45/15 = 3 times.
Answer: When the water temperature changes by 45 ºС, 3 times more heat will be consumed.
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