The same work was done in the two circuits. In one of them, a charge of 15 Kl passed, and in the other 45 Kl.

The same work was done in the two circuits. In one of them, a charge of 15 Kl passed, and in the other 45 Kl. In which circuit is the voltage greater and how many times?

Problem data: q1 (charge that passed through the first indicated circuit) = 15 C; q2 (charge that passed through the second circuit) = 45 C; A (work done) = A1 = A2.

To calculate the voltage ratio on the indicated circuits, we use the ratio: U1 / U2 = n = (A / q1) / (A / q2) = q2 / q1.

Calculation: n = 45/15 = 3 p.

Answer: The voltage on the first indicated circuit is 3 times more.