The scheme of transformations K-KOH-X-Fe2O3 is given.Write the molecular equations of reactions
The scheme of transformations K-KOH-X-Fe2O3 is given.Write the molecular equations of reactions For the second transformation, write an abbreviated ionic equation
Given a homologous chain of substances, consider the chemical reactions that are needed to transform it.
1) A chemical reaction takes place between substances such as potassium and water. Potassium hydroxide is formed and hydrogen gas is evolved. The molecular equation of the reaction can be written as follows:
2 K + 2 H2O = 2 KOH + H2
2) Next, we take the potassium hydroxide obtained in the previous reaction and add the ferric sulfate salt in the solution. Formed ferric hydroxide and potassium sulfate salt. The molecular equation of the reaction can be written as follows:
6 KOH + Fe2 (SO4) 3 = 2 Fe (OH) 3 + 3 K2SO4
The ionic reaction equation can be written as follows:
6 K + + 6 OH – + 2 Fe 3+ + 3 SO4 2- = 2 Fe (OH) 3 + 6 K + + 3 SO4 –
An abbreviated ionic equation can be written as follows:
2 Fe 3+ + 6 OH – = 2 Fe (OH) 3
3) The last reaction is the decomposition of ferric hydroxide into iron oxide and water.
2 Fe (OH) 3 = Fe2O3 + 3 H2O.