The section of the electrical circuit consists of two parallel-connected conductors with resistances

| February 1, 2021 | education

The section of the electrical circuit consists of two parallel-connected conductors with resistances R1 = 3 ohms and R2 = 6 ohms. The current strength in the unbranched part of the circuit is I = 3 A. Determine the power of the current passing through the second conductor.

Since the section of the electrical circuit consists of two parallel-connected conductors, the voltage on these conductors will be the same. According to Ohm’s law for a section of the circuit, there is a directly proportional relationship I = U / R between the current I and the voltage U. Let us express the voltage U from this formula, we get: U = I ∙ R = I1 ∙ R1 = I2 ∙ R2, where R is the resistance of this entire section of the circuit, R1 = 3 ohms and R2 = 6 ohms are the resistances of the parallel-connected conductors. Since, by condition, the current strength in the unbranched part of the circuit is I = 3 A, then I1 = I – I2, then (I – I2) ∙ R1 = I2 ∙ R2. Substitute the values ​​of physical quantities into the expression and find the value of the current flowing through the second conductor: (3 – I2) ∙ 3 = I2 ∙ 6; 9 – 3 ∙ I2 = 6 ∙ I2; I2 = 1 A. To determine the power of the current P2 passing through the second conductor, we use the formula: P2 = I2 ^ 2 ∙ R2; P2 = (1 A) ^ 2 ∙ (6 Ohm) = 6 W.
Answer: 6 W.



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