The sections AC and BD are parallel. Segments AB and CD intersect at point O. Prove that AO = CO and BO = DO.

Given: ACIIBD, AC and BD peres. including about
D-th: AO = CO, BO = DO
Q: Consider triangle ACO and DOB, because AC and BD are parallel, then it follows that the angle C is equal to the angle D and the angle A is equal to the angle B on the basis of parallel straight lines, it follows that the triangles. AOC = triug.DOB on the 2 sign of equality is a triangle, therefore they are isosceles, it follows that AO = CO and BO = DO.