The segment AK is perpendicular to the plane of the rectangle ABCD. Find KC if AK = 2√14 m, AB = 5m, AD = 12m.

Let us determine through what number of meters the length of the AC diagonal of our rectangle will be expressed, when it is known from the condition of the task that its dimensions are 5 and 12 meters, respectively:

√ (12 ^ 2 + 5 ^ 2) = √ (144 + 25) = √169 = 13.

It is obvious that AC is the projection of the KC and the leg of the KCA triangle.

Let us determine through what number of meters the length of the COP will be expressed, when it is known from the condition of the task that the AC is equal to 2√14:

√ (13 ^ 2 + (2√14) ^ 2) = √ (169 + 56) = √225 = 15.

Answer: COP will be equal to 15 m.