The segments AB and CD are halved by the intersection point. Prove that triangle DOA = triangle COB.
| February 6, 2021 | education
Since the segments AB and CD are divided in half by the point O, then AO = OB and CO = OD.
Consider triangles ΔDOA and ΔCOB:
1) AO = OB (see above);
2) CO = OD (see above);
3) ∠AOD = ∠COB (as vertical corners).
Thus, the triangles ΔDOA and ΔCOB are equal in two sides and the angle between them.
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