The segments AC and BD are the diameters of the circle with the center O. The angle ACB is 78 °. Find the AOD corner.
| May 17, 2021 | education
The ВOС triangle is isosceles with the BC base, since OB = OС = R.
Then the angle ОВС = ОВС = АСВ = 75.
The sum of the inner angles of the triangle is 180, then the angle BOC = (180 – 75 – 75) = 30.
Angle AOD = BOC = 30 as vertical angles at the intersection of diameters AC and BD.
Answer: The value of the angle AOD is 30.
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