The segments AC and BD intersect and the intersection point is divided in half. Prove that triangles ABC and CDA are equal.
| January 13, 2021 | education
By condition, point O is the middle of the segments AC and BC, then AO = OC, BO = OD.
Then the quadrilateral AВСD parallelogram according to the third criterion, the diagonal of the parallelogram, at the point from the intersection is divided in half.
By the property of a parallelogram, the diagonal divides it into two equal triangles, then triangles ABC and СAD are equal, which was required to prove.
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