The segments of blood pressure and BC intersect at point O and are divided by this point by sex.

The segments of blood pressure and BC intersect at point O and are divided by this point by sex. find the angle of AСD if angle ABC = 64 ° angle AСO = 56 °

We carry out the drawing. AD intersects with BC, point O is the point of intersection. BO = CO, AO = DO. Angle ABC = 64 °, angle ACO = 56 °.

Consider triangles AOB and COD: BO = CO (by condition), AO = AO (by condition), the angle BOA is equal to the angle COD (vertical). Consequently, the triangles AOB and COD are equal (on two sides and the angle between them).

This means that the angle DCO is equal to the angle ABC = 64 °.

Hence the angle AСD = angle AСO + angle СOD = 56 ° + 64 ° = 120 °.

Answer: the AСD angle is 120 °.