# The semi-major axis of Neptune’s orbit is 30.07 AU. Calculate the period of its revolution around the Sun.

To find the value of the period of Neptune’s rotation around the Sun, we apply Kepler’s third law: Tn ^ 2 / Tz ^ 2 = an ^ 3 / az ^ 3, whence we express: Tn = √ (an ^ 3 * Tz ^ 3 / az ^ 3).

Constants: en – semi-major axis of the planet Neptune’s orbit (by condition an = 30.07 AU); Tz is the period of the Earth’s rotation (T = 1 year); az is the semi-major axis of the Earth’s orbit (az = 1 AU).

Calculation: Tn = √ (an ^ 3 * Tz ^ 3 / az ^ 3) = √ (30.07 ^ 3 * 1 ^ 3/1 ^ 3) = 164.89 years.

Answer: The orbital period of the planet Neptune, according to the calculation, is 164.89 years. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.