The side AB of the quadrilateral ABCD is equal to the side of the square, the perimeter of which is 24 cm. The side CD is 4 cm more

The side AB of the quadrilateral ABCD is equal to the side of the square, the perimeter of which is 24 cm. The side CD is 4 cm more than AB and 3 cm less than CB. Side AD is 20 mm more than the sum of the sides AB and CD. Find the perimeter of the quadrilateral.

24/4 = 6 cm – AB side
6 + 4 = 10 cm – CD side
10 + 3 = 13 cm – side NE
(6 + 10) + 2 = 18 cm – AD side
P = AB + CB + CD + AD = 6 + 13 + 10 + 18 = 47 cm
Answer: P = 47 cm