The side of a regular hexagon is 2 m. Find its area.

Let’s draw six segments from the center of this hexagon to the vertices of this hexagon.

Then we get six identical equilateral triangles, of which a hexagon is added, and the area of ​​this hexagon will be equal to the sum of the areas of six equilateral triangles.

Let’s find the area of ​​one such regular triangle.

Since the length of the side of such a regular is equal to the length of the side of the hexagon and is 2 meters, the area of ​​the triangle is 2 * 2 * sin (60 °) / 2 = 2 * sin (60 °) = 2 * √3 / 2 = √3 m ^ 2.

Therefore, the area of ​​the hexagon is 6√3 m ^ 2.

Answer: 6√3 m ^ 2.