The side of a triangle is 24, and the height to that side is 19. Find the area of the triangle.

Given:
triangle ABC,
ВН – the height drawn to the side of the AС,
AC = 24,
BH = 19.
Find the area of the triangle ABC, that is, S ABC -?
Decision:
Consider a triangle ABC.
The area of a triangle is equal to the product of the height by 1/2 of the side to which this height is drawn.
Hence
S abc = 1/2 * ВН * AC;
S abc = 1/2 * 19 * 24;
S abc = 19 * 24/2;
S abc = 12 * 19;
S abc = 228.
Answer: S abc = 228.