The side of an isosceles triangle is 13 cm larger than its base. The perimeter of the triangle is 68 cm

The side of an isosceles triangle is 13 cm larger than its base. The perimeter of the triangle is 68 cm. Find the sides of the triangle.

Let us express the base of the triangle in terms of z, then the side side will be equal to z + 13. Write the equation:

z + (z + 13) + (z + 13) = 68;

z + z + 13 + z + 13 = 68;

z + z + z = 68-13-13;

2z + z = 68-13-13;

3z = 68-13-13;

3z = 42;

z = 42: 3;

z = 14 cm – the base of the triangle.

Find the side:

14 + 13 = 27 cm – side.

Answer: the base is 14 cm, the sides are 27 cm.