The side of an isosceles triangle is 15 cm, and the base is 24 cm. What is the area of the triangle?

The area of an isosceles triangle along 2 sides S = b / 4 × √ (4a2 – b2), a – equal sides, b – the base of the triangle.
We get 24/4 × √ (4 × 225 – 576) = 108.



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