The side of an isosceles triangle is 17 cm and the base is 16 cm. Find the height drawn to the base.

univerkov | July 18, 2021 | education

Let’s use the picture for the solution.

Since the triangle is equilateral, the height BD divides the base of the AC in half.

Then AD = AC / 2 = 16/2 = 8.

Consider a right-angled triangle ABD and by the Pythagorean theorem AB² = AD² + BD².

Then BD² = AB² – AD² = 17² – 8² = 289 – 64 = 225.

BD = √225 = 15.

Answer: Height BD is 15 cm.

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