The side of an isosceles triangle is 9 cm and its base is 5 cm larger. Find the perimeter of the triangle.

Let’s find the length of the base of this isosceles triangle.

According to the condition of the problem, the length of the lateral side of this isosceles triangle is 9 cm, and the base of this triangle is 5 cm longer than its lateral side, therefore, the length of the base of this triangle is:

9 + 5 = 14 cm.

Find the perimeter of this isosceles triangle.

Since the lengths of the two lateral sides of this triangle are 9 cm, and the length of the third side is 14 cm, then the perimeter P of this triangle is:

P = 9 + 9 + 14 = 18 + 14 = 32 cm.

Answer: the perimeter of this triangle is 32 cm.