The side of the base of the regular quadrangular pyramid is 14 dm and the height is 24 dm.
The side of the base of the regular quadrangular pyramid is 14 dm and the height is 24 dm. Find the volume of the cone inscribed in the pyramid.
To find the volume of the cone, use the formula:
V к = 1/3 * π * r² * h.
The height of the cone is equal to the height of the pyramid, the radius is half the side of the base (at the base is a square).
V к = 1/3 * π * 7² * 24 = 392π (dm³).
Another solution is possible.
We find the volume of this pyramid:
V p = 1/3 * S * h = 1/3 * 14² * 24 = 1568 (dm³).
For a regular quadrangular pyramid, the ratio of the volume of an inscribed cone to the volume of a regular pyramid is:
Vк / Vп = π / 4, from which it follows:
Vк = Vп * π / 4 = 1568 * π / 4 = 392π (dm³).
Answer: the volume of the inscribed cone is 392π dm³.