The side of the rhombus is 11 and the acute angle of the rhombus is 60.

The side of the rhombus is 11 and the acute angle of the rhombus is 60. Find the length of the smaller diagonal of the rhombus.

In a rhombus, the opposite angles are equal, and the sum of the angles is 360, then the angle ABC = (360 – 60 – 60) / 2 = 120.

Then the angle ABO = ABC / 2 = 120/2 = 60.

In triangle ABD, angle ABD = BAD = 60, therefore, angle ADB 60, then triangle ABD is equilateral and AB = AD = BD = 11 cm.

Answer: The smaller diagonal is 11 cm.



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