The side of the rhombus is 25 cm, the height is 24. Find the diagonals of the rhombus.

Since ВН is the height to the CD side, the ВНС and ВНD triangles are rectangular.

Consider a triangle ВНD in which, according to the condition, ВС = 25 cm as a side of a rhombus, ВН = 24 cm as a height.

Then, by the Pythagorean theorem, the leg CH ^ 2 = BC ^ 2 – BP ^ 2 = 625 – 576 = 49.

CH = 7 cm.

Then DH = DC – CH = 25 – 7 = 18 cm.

Consider the triangle ВНD and find, by the Pythagorean theorem, the hypotenuse ВD, which is one of the diagonals of the rhombus.

BD ^ 2 = BH ^ 2 + DH ^ 2 = 24 ^ 2 + 18 ^ 2 = 576 + 324 = 900.

ВD = 30 cm.

Consider a right-angled triangle BOS, in which BC = 25 cm, BO = BD / 2 = 15 cm.

Then, by the Pythagorean theorem, OС ^ 2 = BC ^ 2 – ВO ^ 2 = 25 ^ 2 – 15 ^ 2 = 625 – 225 = 400.

OС = 29 cm.

Then the diagonal AC = 2 * OC = 40 cm.

Answer: The diagonals of the rhombus are 30 cm and 40 cm.



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