# The side of the rhombus is 26 and the acute angle is 60 °. The height of the rhombus, dropped from the top

The side of the rhombus is 26 and the acute angle is 60 °. The height of the rhombus, dropped from the top of the obtuse angle, divides the side into two segments. Find the product of the lengths of these segments.

Consider a triangle ABH, in which the angle A = 60, BH is the height drawn to the side AD, then the angle AHB = 90, and the angle ABH = 180 – 90 – 60 = 30.

The leg AH, right-angled triangle ABH, is located opposite the angle 30, therefore it is equal to half of the hypotenuse. AH = AB / 2 = 26/2 = 13 cm.

In a rhombus, all sides are equal, then the segment DH = AD – AH = 26 – 13 = 13 cm.

The product of the segments AH * DH = 13 * 13 = 169.

Answer: The product of the segments is 169.

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