The side of the rhombus is 8. The radius of the circle inscribed in this rhombus is 2. Find the area of the rhombus.

From the center of the circle, construct the radius OH to the point of tangency N.

OH is the height of the right-angled triangle AOB, then Sosv = AB * OH / 2 = 8 * 2/2 = 8 cm2.

The diagonals of the rhombus divide it into four equal triangles, then Savsd = 4 * Saov = 4 * 8 = 32 cm2.

Answer: The area of the rhombus is 32 cm2.



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