The side of the square is 16 cm. The length of the rectangle is 80 cm, and the width is 2 times less.
The side of the square is 16 cm. The length of the rectangle is 80 cm, and the width is 2 times less. Find the perimeter of each figure. Compare the perimeter of the figures. Find the sum of the perimeters of all figures
We calculate the perimeter of a square by multiplying the length of its side by 4:
Р1 = 4 * 16 = 64 (cm).
To find the perimeter of a rectangle, find its width. To do this, divide the length by 2, since by condition its width is 2 times less than the length:
a = 80/2 = 40 (cm).
To find the perimeter of a rectangle, find the sum of its length and width and multiply by 2:
P2 = 2 * (80 + 40) = 240 (cm).
We see that P2> P1. This means that the perimeter of the rectangle is greater than the perimeter of the square. Let’s find their sum:
Р1 + Р2 = 64 + 240 = 304 (cm).
Answer: 304 cm.