The side of the square is 40 cm. Two ants began to move from vertex A in different directions along

| May 2, 2021 | education

The side of the square is 40 cm. Two ants began to move from vertex A in different directions along the perimeter of the square. One moves at a speed of 1 cm / s, while the other moves 2 times faster. What is the distance between them in 20 seconds?

To solve the problem, you first need to determine the total perimeter of the square.
To do this, multiply the length of one side by the number of sides.
We get:
40 * 4 = 160 cm.

We find the distance that 1 ant will overcome.
1 * 20 = 20 centimeters.

Find the speed of the second ant.
1 * 2 = 2 cm / s.

We find the distance that the second ant will cover.
2 * 20 = 40 centimeters.

Find the total distance.
20 + 40 = 60 centimeters.

In this case, the back between the ants will be 60 cm, and in front: 160 – 60 = 100 cm.



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