The side of the square is 6 and the sides of the rectangle are 4 cm and 9 cm. Compare the area and perimeter of these figures.
1) First of all, we find the area of a square, the side of which is 6 cm, by squaring this value:
S = 6² = 36 (cm²).
We calculate the perimeter of a square with a side of 6 cm, increasing the length by 4 times:
P = 4 * 6 = 24 (cm).
2) Now we calculate the area of a rectangle with sides 4 cm and 9 cm by multiplying the length of the rectangle by its width:
S = 4 * 9 = 36 (cm²).
We calculate, in turn, the perimeter of the rectangle, equal to the doubled sum of its two sides:
P = 2 (4 + 9) = 2 * 13 = 26 (cm).
Thus, the area of a square with a side of 6 cm and the area of a rectangle with sides of 4 cm and 9 cm are equal.
The perimeter of a square with a side of 6 cm is 2 cm less than the perimeter of a rectangle with sides of 4 cm and 9 cm, since 26 – 24 = 2 (cm).