The side of the square was reduced by 10%. By how many% and how has the area of the square

The side of the square was reduced by 10%. By how many% and how has the area of the square, the perimeter of the square changed?

In order to solve the first problem, we will perform the following actions:

1) Suppose the square has a side of 10.

2) Then the area is 100.

3) Reduce the side by 10%: area = 81.

4) The difference is 19%.

5) The perimeter was initially 40 and became 36, that is, it changed by 10%.

Answer: the area changed by 19% and the perimeter by 10%.



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