The side of the trapezoid 4 and one of the adjacent corners of 30 degrees, find the area of the trapezoid

The side of the trapezoid 4 and one of the adjacent corners of 30 degrees, find the area of the trapezoid if its base is 2.6. and 7.4.

From the top B of the trapezoid ABCD, we will construct the height BH.

Triangle ABH is rectangular, in which the angle BAН, by condition, is equal to 30.

The BH leg lies opposite an angle of 30, then its length is equal to half the length of the AB hypotenuse.

BH = AB / 2 = 4/2 = 2 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * ВН / 2 = (2.6 + 7.4) * 2/2 = 10 cm2.

Answer: The area of the trapezoid is 10 cm2.



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