The side of the trapezoid is 4, and one of the adjacent angles of 30 degrees find the area if its bases are 4 and 8.

Let’s build the height of the HВ trapezoid ABCD.

In a right-angled triangle ABН, the ВН leg lies opposite the angle 30, then its length is equal to half the length of the hypotenuse AB, BH = AB / 2 = 4/2 = 2 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * ВН / 2 = (4 + 8) * 2/2 = 12 cm2.

Answer: The area of the trapezoid is 12 cm2.



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