The side of the triangle is 12 cm, and the height drawn to it is three times less. Find the area of the triangle.

From the condition of the problem it is known that in the triangle Δ ABC, the AC side = 12 cm, and the height of the ВН drawn to it is three times less than this side. Let’s find the height of the triangle: BH = 12 cm: 3 or BH = 4 cm.

To find the area of a triangle, you need to determine what is half the product of the length of the base of the triangle and the length of its height drawn to this base. We get: S = (12 cm · 4 cm): 2 = 48 cm²: 2; or S = 24 cm².

Answer: The area of a triangle is 24 square centimeters.