The sides AB and AC of the isosceles triangle ABC are equal to each other and the angle

The sides AB and AC of the isosceles triangle ABC are equal to each other and the angle BAC is 26 degrees. Find the corners of the triangles.

Since ABC is an isosceles triangle and sides AB and AC are equal lateral sides, angles B and C will be equal angles at the base.

Therefore, since the sum of all the angles of the triangle is 180, and one of them is 26, and the other two are equal to each other, then we compose the equation:
26 + (x + x) = 180;

26O + 2x = 180;

2x = 180 – 26;

x = (180 – 26) / 2 = 77.

Answer: 77.