The sides of one triangle are 6 cm, 15 cm, 8 cm, and the perimeter of a similar triangle is 117 cm.

The sides of one triangle are 6 cm, 15 cm, 8 cm, and the perimeter of a similar triangle is 117 cm. Find the sides of the other triangle.

Let’s denote the coefficient of similarity through x, then the sides of such a triangle will be respectively equal to 6x cm, 15x cm and 8x cm.Since the perimeter of such a triangle is 117 cm, we compose and solve the equation:

6x + 15x + 8x = 117;

29x = 117;

x = 117: 29;

x = 117/29.

The coefficient of similarity is 117/29, then the sides of a similar triangle will be:

6 * 117/29 = 702/29 = 24 6/29 (cm);

15 * 117/29 = 1755/29 = 60 15/29 (cm);

8 * 117/29 = 936/29 = 32 8/29 (cm);

Answer: the sides of such a triangle are 24 6/29 cm, 60 15/29 cm and 32 8/29 cm.